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In geometry, a median of a triangle is a line segment joining a vertex to the midpoint of the opposing side. Every triangle has exactly three medians: one running from each vertex to the opposite side. In the case of isosceles and equilateral triangles, a median bisects any angle at a vertex whose two adjacent sides are equal in length.
Each median of a triangle passes through the triangle's centroid, which is the center of mass of an object of uniform density in the shape of the triangle. Thus the object would balance on any line through the centroid, including any median.
Each median divides the area of the triangle in half; hence the name. (Any other lines which divide the area of the triangle into two equal parts do not pass through the centroid.) The three medians divide the triangle into six smaller triangles of equal area.
Consider a triangle ABC. Let D be the midpoint of , E be the midpoint of , F be the midpoint of , and O be the centroid.
By definition, . Thus and , where represents the area of triangle ; these hold because in each case the two triangles have bases of equal length and share a common altitude from the (extended) base, and a triangle's area equals one-half its base times its height.
Since , therefore, . Using the same method, you can show that .
The lengths of the medians can be obtained from Apollonius' theorem as:
where a, b and c are the sides of the triangle with respective medians ma, mb, and mc from their midpoints.
Thus we have the relationships:
The centroid divides each median into parts in the ratio 2:1, with the centroid being twice as close to the midpoint of a side as it is to the opposite vertex.
For any triangle,
For any triangle with sides and medians ,
The medians of a right triangle with hypotenuse c satisfy
We can express any triangle's area T in terms of its medians ma, mb, and mc as follows. Denoting their semi-sum (ma + mb + mc)/2 as σ, we have
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